Use euclids divison to find hcf of 900and270
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1
the hcf of 900and 270
=90
=90
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5
here,
900>270
therefore by Euclid division lemma
a=bq+r where 0≤ r< b
900 = 270 × 3 + 90
=> 270 = 90 × 3 + 0
since, last remainder is 90,
therefore HCF = 90
900>270
therefore by Euclid division lemma
a=bq+r where 0≤ r< b
900 = 270 × 3 + 90
=> 270 = 90 × 3 + 0
since, last remainder is 90,
therefore HCF = 90
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