Use eudclid's division algorithm to find the highest common factor(hcf)of (i)340and 412,(ii)867and255,(iii)10224and9648,(iv)84,90and120.
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I.) 412=340*1+72
340=72*4+52
72=52*1+22
52=22*2+8
22=8*2+4
8=4*2+0
The hcf is 2
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Step-by-step explanation:
b=hcf
hope helps you mate
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