use eulid's division algorithm to find the HCF of 3696 and 273 ?
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HCF OF (3696,273) IS AS FOLLOWS :
3696 = 273 × 13 + 147
273 = 147 × 1 + 126
147 = 126 × 1 + 21
126 = 21 × 6 + 0
Hence HCF of 3696 and 273 is .
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3696 = 273 × 13 + 147
273 = 147 × 1 + 126
147 = 126 × 1 + 21
126 = 21 × 6 + 0
Hence HCF of 3696 and 273 is .
Hope you like it please mark as brainliest and follow me if you like my answer.
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