use factor theoram 2ycube -5ysquare -19y+42
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Evaluate for y=2
2(2^3)−5(2^2)−(19)(2)+42
=0
So,y-2 is the factor of the expression
2y^3−5y^2−19y+42/y-2
=2y^2-y-21
(y-2) (2y^2-y-21)
(y-2) (2y−7)(y+3)
2(2^3)−5(2^2)−(19)(2)+42
=0
So,y-2 is the factor of the expression
2y^3−5y^2−19y+42/y-2
=2y^2-y-21
(y-2) (2y^2-y-21)
(y-2) (2y−7)(y+3)
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