Question

Use factor theorem to check whether (x-1) is a factor of 2√2x^3+5√2x^2-7√2

Answer 1

Answer:

x-1=0

x=0+1

x=1

put x=1 in giving statement

$2 \sqrt{2x3} + 5 \sqrt{2x {}^{2} } - 7 \sqrt{2}$

$2 \sqrt{2(1)3} + 5 \sqrt{2(1) {}^{2} } - 7 \sqrt{2}$

$2 \sqrt{2} + 5 \sqrt{2} - 7 \sqrt{2}$

$+ 7 \sqrt{2} - 7 \sqrt{2}$

0

Answer 2

Step-by-step explanation:

x-1=0

x=0+1

x=1

put x=1 in giving statement

2 \sqrt{2x3} + 5 \sqrt{2x {}^{2} } - 7 \sqrt{2}2

2x3

+5

2x

2

−7

2

2 \sqrt{2(1)3} + 5 \sqrt{2(1) {}^{2} } - 7 \sqrt{2}2

2(1)3

+5

2(1)

2

−7

2

2 \sqrt{2} + 5 \sqrt{2} - 7 \sqrt{2}2

2

+5

2

−7

2

+ 7 \sqrt{2} - 7 \sqrt{2}+7

2

−7

2

0 hope it works