Question

use factor theorem to determine whether q x is a factor of PX in the following case PX equal to 2 x cube + 4 x + 6 and qx is equal to X + 1​

Answer 1

Answer:

(x+1) is a factor of p(x).

Step-by-step explanation:

x+1=0

x=-1

p(x)=2x^3+4x+6. (substitute x=-1)

=-2-4+6

=-6+6

=0

Therefore q(x) is a factor of p(x)

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