use factor theorem to factorise the following polynomials
1} 6x³-7x²-8x+5
2}2x⁴-13x³+28x²-23x+6
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Answer:
2. ax⁴ + b x³ + c x² + d x + e= 0
akar akar x1, x2 , x3 dam x4
x1 + x2 + x3 + x4 = -b/a
x1x2 + x1x3+ x1x4 + x2x3 +x2 x4 + x3 x4 = c/a
x1x2x3 + x1 x2 x4 + x1 x3 x4 + x2 x3 x4 = -d/a
x1 x2 x3 = e/a
Penjelasan dengan langkah-langkah:
2x⁴ + 13 x³ + 28 x² + 23x + 6= 0
a= 2, b = 13, c = 28 , d= 23 , e = 6
akar akar x1, x2 , x3 dam x4
..
jumlah hasil kali ketiga akar
x1x2x3 + x1 x2 x4 + x1 x3 x4 + x2 x3 x4 = -d/a
= -23/2
= -11.5
Step-by-step explanation:
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