Use factor theorem to prove that (x a) is a factor of (x^n a^n) for any odd positive integer 'n'.
Answers
Step-by-step explanation:
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Answer:
Let p(x) = x^n + a^n , where n is odd positive integer.
Take (x+a)= 0
=> x = -a
Consider:
p(-a) = (-a) ^n + (a) ^n
= -a^n + a^n
= 0
Since, n is odd.
By Factor theorem,
(x+a) is a factor of p(x) when n is odd positive integer.
Step-by-step explanation: