Use factor theorem to show that;
(X-2) is a factor of the polynomial X³-X-6
(X+2)(X-1) is a factor of the polynomial
P(X)=X⁴+X³+2X²+4X²-8
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let
f(x)=x³-x-6,
if (x-2) is a factor of f(x), then f(2) should be equal to zero,
then
f(2)=2³-2-6,
f(2)=8-8=0,
since
f(2)=0,
therefore (x-2) is a factor of f(x).
f(x)=x³-x-6,
if (x-2) is a factor of f(x), then f(2) should be equal to zero,
then
f(2)=2³-2-6,
f(2)=8-8=0,
since
f(2)=0,
therefore (x-2) is a factor of f(x).
ssanjana9:
thanks...
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