Question

Use factor theorem to show that x4+2x3-2x2+2x-3 is exactly divisible by (x+3).

Answer 1

Step-by-step explanation:

since by facor therom ( reminder therom) we know that if x-a is factor of any function f(x) then

x-a=0,putting x=a in given function

then if F(a) =0 then x-a is the factor of f(x)

now putting x=-3 in given expression

then it give the value 0

hence x+a is the factor of given expression

please mark as brainliest

Answer 2

Answer:

Let p(x)=x4+2x3−2x2+2x−3andg(x)=x+3. Then , g(x)=0⇒x+3=0⇒x=−3.

By factor theorem , p (x) will be exactly divisible by x+3 , if p(−3)=0.

Now , p(−3)={(−3)4+2×(−3)3−2×(−3)2+2×(−3)−3}

=(81−54−18−6−3)=0.

Since p(−3)=0 , it follows that p (x) is exactly divisible by (x+3).

HOPE IT HELP U

PLEASE MARK ME AS A BRAINLIST ANSWER......