Use factor theorem to verify that (x+a) is a factor of x ki power n + A ki power n for any odd positive integer
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Let f (x)=x^n + a^n
x+a will be the factor of f(x), if f (-a)=0
Now, f (-a) = (-a)^n + a^n=0 (since 'n' is a odd positive integer).
Thus, x+a is a factor of x^n+a^n.
x+a will be the factor of f(x), if f (-a)=0
Now, f (-a) = (-a)^n + a^n=0 (since 'n' is a odd positive integer).
Thus, x+a is a factor of x^n+a^n.
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4
Answer:
Let p(x) = x^n + a^n , where n is odd positive integer.
Take (x+a)= 0
=> x = -a
Consider:
p(-a) = (-a) ^n + (a) ^n
= -a^n + a^n
= 0
Since, n is odd.
By Factor theorem,
(x+a) is a factor of p(x) when n is odd positive integer.
Step-by-step explanation:
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