Question

use factor theorm show that X+1 is a factor of x¹⁹+1







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Answer 1

Answer:

zero

Step-by-step explanation:

x+1 = 0

=> x = -1

$f(x) = {x}^{19} + 1 \\ = > f( - 1) = ({ - 1})^{19} + 1 \\ \: \: \: \: \: \: \: = - 1 + 1 \\ = 0$