Math, asked by sunandatalgaonkar28, 3 months ago

use formula to find the values​

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Answers

Answered by rk156747
1

Answer:

(1) (100+8)(100+8)= 100×100+8×8+2×100×8

=10000+64+1600=11664

in the same fashion 2,3, 4 will be solved

(5). 77×83= (80-3)×(80+3)= 80×80-3×3= 6400-9=6391

the same way 6 will be solved

Answered by Swapnilbro
1

Answer:

Q4.

i. (108)^2

=(100+8)^2 108=100+8

=100^2+8^2+2(100) (8) [(a+b)^2=a^2 +b^2 +2ab]

=10000+64+1600

=11664

ii. (904)^2

=(900+4)^2 904=900+4

=900^2+4^2+2(900)(4) [(a+b)^2=a^2 +b^2 +2ab]

=810000+16+7200

=817216

iii. (195)^2

=(200-5)^2 [(a-b)^2=a^2 +b^2 -2ab]

=200^2+5^2-2(200)(5)

=40000+25-2000

=38025

iv. (82)^2

=(80+2)^2 [(a+b)^2=a^2 +b^2 +2ab]

=80^2+2^2+2(2) (80)

=6400+4+320

=6724

v. 77x83

=(80-3) (80+3) (a+b) (a-b) = a^2-b^2

=80^2-3^2

=6400-9

=6391

vi. 196x204

=(200-4) (200+4) (a+b) (a-b) = a^2-b^2

=200^2-4^2

=40000-16

=39984

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