Question

Use Graph Paper For This Question. Draw The Graph Of 3X-2y=5 and 2X=3Y On The Same Axes. Use 2Cm = 1 Unit On Both The Axes And Plot Only 3 Points Per Line. Write Down The Co-Orditnates Of The Point Of Intersection Of The Two Lines. Also Find The Area Of The Triangle Formed By The Lines And Y-Axis​

Answer 1

Answer:

SOLUTION:

Given pair of Linear Equations are:

3x - 4y +3 =0 ……………….(1)

3x + 4y - 21 = 0 …………….(2)

Put x= 3 in eq 1

3x - 4y +3 =0

3×3 - 4y +3= 0

9 - 4y = - 3

9 +3 = 4y

12 = 4y

y = 12/4= 3

A(3, 3)

Put y= 0 in eq 1

3x - 4 × 0 = -3

3x = -3

x =- 3/3 = -1

B(-1,0)

Put x= 3 in eq 2

3x + 4y -21 =0

3×3 + 4y = 21

9 + 4y = 21

4y = 21 -9

4y = 12

y = 12/4= 3

A(3, 3)

Put y= 0 in eq 2

3x + 4×0= 21

3x + 0 = 21

3x = 21

x = 21/3

x = 7

x = 2

C(7,0)

TABLE AND GRAPH are on the ATTACHMENT.

The coordinates of the vertices of ∆ABC are A(3, 3) , B(-1,0) & C(7,0)

Area of ∆ ABC = ½ (base × height)

Area of ∆ ABC = ½ (AM × BC)

[From the graph , AM = 3 , BC = 8]

Area of ∆ ABC = ½ (3 × 8) = 24/2 = 12 sq units.

HOPE THIS WILL HELP YOU

Plz mark brainliest ❤️❤️❤️❤️❤️

Step-by-step explanation: