Use Hund’s rule to derive the electronic configuration of Ce³⁺ ion, and calculate its magnetic moment on the basis of ‘spin-only’ formula.
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Magnetic moment can be calculated as:

Where,
n = number of unpaired electrons
The electronic configuration of Ce3+ : 1s22s22p63s23p63d104s24p64d105s25p64f1
In Ce3+, n = 1
∴ μ = 1 ( 1 +2 )‾‾‾‾‾‾‾‾‾‾√ = 3‾√ = 1.732 B.M

Where,
n = number of unpaired electrons
The electronic configuration of Ce3+ : 1s22s22p63s23p63d104s24p64d105s25p64f1
In Ce3+, n = 1
∴ μ = 1 ( 1 +2 )‾‾‾‾‾‾‾‾‾‾√ = 3‾√ = 1.732 B.M
Answered by
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Hey !!
₅₈Ce = [Xe]⁵⁴ 4f¹ 5d¹ 6s²
Ce³⁺ = [Xe]⁵⁴ 4f¹, there is only one unpaired electron, n = 1
Hence, μ = √n (n+2)
= √1 (1+2)
= √3
FINAL RESULT = 1.73 BM
Good luck !!
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