Question

Use identities to evaluate (101)²​

Answer 1

Answer:

$(100 + 1) ^{2}$

(a+b)^2=(a)^2+(b)^2+2ab

$(100) ^{2} + (1) ^{2} + 2 \times 100 \times 1$

$10000 + 1 + 200$

$10201$

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Answer 2

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