Math, asked by Swift11, 1 year ago

use identities to evaluate (101)²

Answers

Answered by Robinhood111
13
101

(100+1)^2

(100)^2 + 2(100)(1) +( 1)^2

10000+200+1

=10201

mona126: right
Answered by varunvbhat26
0

Answer: 10201

Step-by-step explanation:

We can evaluate this easily, without actually multiplying, by using the following identity.

(a + b)² = a² + b² + 2ab

We can write 101 = 100 + 1.

(101)²

= (100 + 1)²

= (100)² + (1)² + 2(100)(1)

= 10000 + 1 + 200

= 10201

More information:

Have you wondered why (a + b)² = a² + b² + 2ab? Read on if you don't know and want to know.

(a + b)²

= (a + b)(a + b)

=  a(a + b) + b(a + b)

= a² + ab + ab + b²

= a² + 2ab + b²

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