use identities to evaluate (101)²
Answers
Answered by
13
101
(100+1)^2
(100)^2 + 2(100)(1) +( 1)^2
10000+200+1
=10201
(100+1)^2
(100)^2 + 2(100)(1) +( 1)^2
10000+200+1
=10201
mona126:
right
Answered by
0
Answer: 10201
Step-by-step explanation:
We can evaluate this easily, without actually multiplying, by using the following identity.
(a + b)² = a² + b² + 2ab
We can write 101 = 100 + 1.
(101)²
= (100 + 1)²
= (100)² + (1)² + 2(100)(1)
= 10000 + 1 + 200
= 10201
More information:
Have you wondered why (a + b)² = a² + b² + 2ab? Read on if you don't know and want to know.
(a + b)²
= (a + b)(a + b)
= a(a + b) + b(a + b)
= a² + ab + ab + b²
= a² + 2ab + b²
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