Question

use identities to solve this.... ​

Answer 1

Step-by-step explanation:

LHS

( sinO/cosO= tanO)

so

(sino/coso+sino/sino/coso-sino)

now take common sino out from numerator & denominator & cancel out

(1/coso+1/1/coso-1)

we know (1/coso=seco)

(seco+1/seco-1)