Use identity ( − )
3
to evaluate (95)3
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1
Solution
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(98)
3
(100−2)
3
∴(a−b)
3
=a
3
−b
3
−3a
2
b+3ab
2
(100−2)
3
=(100)
3
−(2)
3
−3×(100)
2
×2+3×100×2
2
=1000000−3−60000+1200
=941192.
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