Question

Use identity to find (3a-17b)²​

Answer 1

Answer:

hope it's help you

Step-by-step explanation:

$(3a−21)(3a−21)=(3a−21)2</p><p></p><p>using identity (a−b)2=a2−2ab+b2</p><p></p><p>(3a−21)2=(3a)2−2×3a×21+(21)2</p><p></p><p>(3a−21)2=9a2−3a+41</p><p></p><p></p><p>$

Answer 2

Answer:

$(3a - 17b)^2 = 9a^2 -102ab + 289b^2$

Step-by-step explanation:

Identity which is used to solve this is $(a- b)^2 = a^2 - 2ab + b^2$

$(3a - 17b)^2 \\= (3a)^2 - 2 (3a) (17b) + (17b)^2\\= 9a^2 - 6a (17b) + 289b^2\\= 9a^2 -102ab + 289b^2$

So, $(3a - 17b)^2 = 9a^2 -102ab + 289b^2$