Use identity to find the square of 103
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103= (100+3)^2
=(100)^2 + 2×100×3 + (3)^2 [(a+b)^2 = (a)^2+ 2×a×b +(b)^2]
=10000+600+9
=10609.
=(100)^2 + 2×100×3 + (3)^2 [(a+b)^2 = (a)^2+ 2×a×b +(b)^2]
=10000+600+9
=10609.
SakshiRaaj:
yes the answer is 10609... plzz look at my soln
ya sorry
it's ok
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