Question

Use identity to find the square of 103

Answer 1

(103)²= (100+3)²


=>
$(x + y) {}^{2} = {x}^{2} + y {}^{2} + 2xy$
we get,
(100+3)² = (100)²+(3)²+2(100)(3)


=> (100+3)² = 10000+9+600

=> 103² = 10609

hope this helps

Answer 2

We can write 103 as 100+3 .
Now, 103^2 = (100+3)^2
By using the identity , (a+b)^2 = a^2+2ab +b^2.
(100+3)^2 = 10000+9+600 = 10609.