Math, asked by komaljotkaur10, 2 months ago

Use identity to solve 1 - 64a³​

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Answers

Answered by rk8810123
1

Answer:

1-(4a)^3

use the property of (a-b)^3

Answered by priyanshukamble533
1

Answer:

i hope its correct answer and helpful

Step-by-step explanation:

1−64a 3 6−12a+48a 2=(1) 3 −(4a) 3 −3(1) 2 (4a)+3(1)(4a) 2

Suitable identities is x 3 −y 3 −3x 2 y+3xy 2 =(x−y) 3

∴(1) 3 −(4a) 3 −3(1) 2 (4a)+3(1)(4a) 2=(1−4a) 3

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