Use identity to solve 1 - 64a³
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Answer:
1-(4a)^3
use the property of (a-b)^3
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Answer:
i hope its correct answer and helpful
Step-by-step explanation:
1−64a 3 6−12a+48a 2=(1) 3 −(4a) 3 −3(1) 2 (4a)+3(1)(4a) 2
Suitable identities is x 3 −y 3 −3x 2 y+3xy 2 =(x−y) 3
∴(1) 3 −(4a) 3 −3(1) 2 (4a)+3(1)(4a) 2=(1−4a) 3
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