use isoceles triangle theorem
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Given: ΔABC is an isosceles triangle
To prove: BE = CF
ABC is an isosceles triangle in which altitudes BE and CF are drawn to equal sides AC and AB respectively .
In ΔAEB and ΔAFC,
∠AEB = ∠AFC (Each 90° as BE and CF are altitudes)
∠A = ∠A (Common angle)
AB = AC (Given ΔABC is an isosceles triangle)
∴ ΔAEB ≅ ΔAFC (By AAS congruence rule)
∴ BE = CF (By CPCT)
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