Hindi, asked by balwinderalti, 5 months ago

use jivan mein main kabhi bhi bura kam nahin Karna chahie ine vakya mein swarnam dhundh Gaye use, bhool Kar, Karam, bura​

Answers

Answered by jaskirat901
1

Answer:

ruk hor kive chal rehi the trip and the average person so I can make sure I will follow up with a constant reminder of our conversation on Friday and half hours to

Answered by Cutekhushi00
1

Explanation:

T-RATIOS:

\begin{gathered}\begin{gathered}\boxed{\boxed{\begin{array}{ |c |c|c|c|c|c|} \bf\angle A &amp; \bf{0}^{ \circ} &amp; \bf{30}^{ \circ} &amp; \bf{45}^{ \circ} &amp; \bf{60}^{ \circ} &amp; \bf{90}^{ \circ} \\ \\ \rm sin A &amp; 0 &amp; \dfrac{1}{2}&amp; \dfrac{1}{ \sqrt{2} } &amp; \dfrac{ \sqrt{3} }{2} &amp;1 \\ \\ \rm cos \: A &amp; 1 &amp; \dfrac{ \sqrt{3} }{2}&amp; \dfrac{1}{ \sqrt{2} } &amp; \dfrac{1}{2} &amp;0 \\ \\ \rm tan A &amp; 0 &amp; \dfrac{1}{ \sqrt{3} }&amp; 1 &amp; \sqrt{3} &amp; \rm Not \: De fined \\ \\ \rm cosec A &amp; \rm Not \: De fined &amp; 2&amp; \sqrt{2} &amp; \dfrac{2}{ \sqrt{3} } &amp;1 \\ \\ \rm sec A &amp; 1 &amp; \dfrac{2}{ \sqrt{3} }&amp; \sqrt{2} &amp; 2 &amp; \rm Not \: De fined \\ \\ \rm cot A &amp; \rm Not \: De fined &amp; \sqrt{3} &amp; 1 &amp; \dfrac{1}{ \sqrt{3} } &amp; 0 \end{array}}}\end{gathered}\end{gathered} </p><p>∠A</p><p>sinA</p><p>cosA</p><p>tanA</p><p>cosecA</p><p>secA</p><p>cotA</p><p>	</p><p>  </p><p>0 </p><p>∘</p><p> </p><p>0</p><p>1</p><p>0</p><p>NotDefined</p><p>1</p><p>NotDefined</p><p>	</p><p>  </p><p>30 </p><p>∘</p><p> </p><p>2</p><p>1</p><p>	</p><p> </p><p>2</p><p>3</p><p>	</p><p> </p><p>	</p><p> </p><p>3</p><p>	</p><p> </p><p>1</p><p>	</p><p> </p><p>2</p><p>3</p><p>	</p><p> </p><p>2</p><p>	</p><p> </p><p>3</p><p>	</p><p> </p><p>	</p><p>  </p><p>45 </p><p>∘</p><p> </p><p>2</p><p>	</p><p> </p><p>1</p><p>	</p><p> </p><p>2</p><p>	</p><p> </p><p>1</p><p>	</p><p> </p><p>1</p><p>2</p><p>	</p><p> </p><p>2</p><p>	</p><p> </p><p>1</p><p>	</p><p>  </p><p>60 </p><p>∘</p><p> </p><p>2</p><p>3</p><p>	</p><p> </p><p>	</p><p> </p><p>2</p><p>1</p><p>	</p><p> </p><p>3</p><p>	</p><p> </p><p>3</p><p>	</p><p> </p><p>2</p><p>	</p><p> </p><p>2</p><p>3</p><p>	</p><p> </p><p>1</p><p>	</p><p> </p><p>	</p><p>  </p><p>90 </p><p>∘</p><p> </p><p>1</p><p>0</p><p>NotDefined</p><p>1</p><p>NotDefined</p><p>0</p><p>

Similar questions