Question

use law of exponents and simply the following​
${7}^{5} \times {7}^{ - 3 } \: \times {7}^{ - 1}$
​

Answer 1

Step-by-step explanation:

7^5×7^-3×7^-1

=7^(5-3-1)

=7^1

=7

Answer 2

Answer:

$\large{\red{\fbox{Given:-}}}$

$\gray{\bold{{7}^{5} \times{7}^{ - 3}\times{7}^{ - 1}}}$

$\large{\red{\fbox{Answer:-}}}$

$\large{\purple{{7}^{5}\times{7}^{ - 3}\times{7}^{ - 1}}}$

$\large{\blue{{7}^{5 + ( - 3) + ( - 1)}}}$

$\large{\blue{{7}^{5 - 3- 1}}}$

$\large{\blue{{7}^{2- 1}}}$

$\large{\orange{{7}^{1} = 7}}$

$\large{\green{\fbox{\fbox{Hope it's help you}}}}$