Question

Use long division following numbers
219,1102,1218​

Answer 1

Answer:

Use long division following numbers

219,1102,1218

Answer 2

Answer:

I hope this helped you

Step-by-step explanation:

HCF (219, 1102, 1218) = 1

Solution :-

First prime factorise 219, 1102, 1218

Prime factorisation of 219

\begin{gathered}\begin{array}{r | l} 3 & 219 \\ \cline{1-2} 73 & 73 \\ \cline{1-2} & 1 \end{array}\end{gathered}

3

\cline1−273

\cline1−2

219

73

1

Prime factorisation of 1102

\begin{gathered}\begin{array}{r | l} 2 & 1102 \\ \cline{1-2} 19 & 551 \\ \cline{1-2} 29 & 29 \\ \cline{1-2} & 1 \end{array}\end{gathered}

2

\cline1−219

\cline1−229

\cline1−2

1102

551

29

1

Prime factorisation of 1218

\begin{gathered}\begin{array}{r | l} 2 & 1218 \\ \cline{1-2} 3 & 609 \\ \cline{1-2} 7 & 203 \\ \cline{1-2} 29 & 29 \\ \cline{1-2} & 1 \\ \end{array}\end{gathered}

2

\cline1−23

\cline1−27

\cline1−229

\cline1−2

1218

609

203

29

1

219 = 3 * 73 * 1

1102 = 2 * 19 * 29 * 1

1218 = 2 * 3 * 7 * 29 * 1

We know that

HCF = Product the smallest power of each common prime factor of the numbers.

But here we dont have any common prime factor.

So 219, 1102, 1218 are co - primes

HCF of any co - primes is 1

HCF (219, 1102, 1218) = 1