Question

use method of contradiction to show that √3 and √5 are irrational numbers​

Answer 1

let assume prove that root 5 is rational number

root 5 =a/b

s.o.b.s

then 5=a/b

a/5b

then our assumption is wrong that root 5 is rational if not then it means "root 5 is rational number"

you do same step to find for root 3 ,root 2

Answer 2

ur supposition is wrong. it is a contradiction.
hence root three + root three is an irrational no . mark me brainliest please