Question

Use molecular orbital theory to explain why the Be₂ molecule does not exist.

Answer 1

As per the molecular orbital theory to explain why the Be₂ molecule does not exist.

The electronic configuration of the  Beryllium is 1s2 2s2.

From the electronic configuration, it is evident that there is no singly filled atomic orbital present in beryllium.

Without the half-filled orbital, the overlapping is not possible.

Therefore Be2 molecule does not exist.

Answer 2

Answer

Be

Be 2

Be 2

Be 2 molecule has MO electronic configuration KK(σs)

Be 2 molecule has MO electronic configuration KK(σs) 2

Be 2 molecule has MO electronic configuration KK(σs) 2 (σ

Be 2 molecule has MO electronic configuration KK(σs) 2 (σ ∗

Be 2 molecule has MO electronic configuration KK(σs) 2 (σ ∗ 2s)

Be 2 molecule has MO electronic configuration KK(σs) 2 (σ ∗ 2s) 2

Be 2 molecule has MO electronic configuration KK(σs) 2 (σ ∗ 2s) 2 .

Be 2 molecule has MO electronic configuration KK(σs) 2 (σ ∗ 2s) 2 .The bond order is

Be 2 molecule has MO electronic configuration KK(σs) 2 (σ ∗ 2s) 2 .The bond order is 2

Be 2 molecule has MO electronic configuration KK(σs) 2 (σ ∗ 2s) 2 .The bond order is 22−2

Be 2 molecule has MO electronic configuration KK(σs) 2 (σ ∗ 2s) 2 .The bond order is 22−2

Be 2 molecule has MO electronic configuration KK(σs) 2 (σ ∗ 2s) 2 .The bond order is 22−2 =0.

Be 2 molecule has MO electronic configuration KK(σs) 2 (σ ∗ 2s) 2 .The bond order is 22−2 =0.Zero bond order indicates that Be

Be 2 molecule has MO electronic configuration KK(σs) 2 (σ ∗ 2s) 2 .The bond order is 22−2 =0.Zero bond order indicates that Be 2

Be 2 molecule has MO electronic configuration KK(σs) 2 (σ ∗ 2s) 2 .The bond order is 22−2 =0.Zero bond order indicates that Be 2

Be 2 molecule has MO electronic configuration KK(σs) 2 (σ ∗ 2s) 2 .The bond order is 22−2 =0.Zero bond order indicates that Be 2 molecule does not exists.