Question

Use Newton-Raphson method to obtain a real root, correct to three decimal places, of the equation:
x^3-5x+3=0.

Answer 1

Answer:

11

Step-by-step explanation:

Answer 2

Given: x^3-5x+3=0

To Find: Use the Newton-Raphson method to obtain a real root, correct to three decimal places, of the equation

Solution:

x^3 −5x+3=0

f(x)= x^3-5x+3

f'(x)=3x^2-5f

X n+1 = Xn - f( Xn)/ f' (Xn)

This implies Xo = -2

And X1 = - 2.491

Then, Xo =1

From the values table, X11 = 0.657

Then Xo= 2

X111= 1.834

Therefore, by the Newton-Raphson method, a real root correct to three decimal places of the equation obtained is X111= 1.834.

#SPJ2