Question

use of linear equations and solve a two digit puzzle a digit at units place is 1 less than twice the digit at tens place sum of the number and interchanged digit number is 121.

pls its urgent​

Answer 1

Answer:

Given units digit is x and tens digit is y

Hence the two digit number = 10y + x

Number obtained by reversing the digits = 10x + y

Given that sum of a two digit number and the number obtained by reversing the order of its digits is 121.

Then (10y+x)+(10x+y)=121

⇒10y+x+10x+y=121

⇒11x+11y=121

⇒x+y=11

hope it helps