USE PIE = 22/7
TRY THIS.........
Answers
SOLUTION :-
=> Radius(r) of gold region (i.e.., 1st circle) = 21/2 = 10.5cm.
=>Given that, each circle is 10.5cm wider than the previous circle.
=>Therefore, radius (r2) of 2nd circle = 10.5 + 10.5 = 21cm.
=> Radius(r3) of 3rd circle = 21+10.5=31.5cm .
=>Radius (r4) of 4th circle = 31.5+10.5 =42cm.
=>Radius(r5) of 5th circle = 42+ 10.5 =52.5cm.
=>(1)Area of gold region = Area of 1st circle
=>Area of gold region = π(r1)²
=>Area of gold region = π(10.5)²
=>.°. Area of gold region = 346.5cm².
=>(2) Area of red region = Area of 2nd circle - Area of 1st circle
=>Area of red region = π(r2)²-π(r1)²
=>Area of red region = π(21)²-π(10.5)²
=>Area of red region = 441π -110.25π
=>Area of red region = 330.75π
=>.°. Area of red region = 1039.5cm².
=>(3)Area of blue region = Area of 3th circle - Area of 2nd circle
=>Area of blue region = π(r3)²-π(r2)²
=>Area of blue region = π(31.5)²-π(21)²
=>Area of blue region = 992.25π -441π
=>Area of blue region = 551.25π
=>.°. Area of blue region = 1732.5cm²
=>(4)Area of black region = Area of 4th circle - Area of 3rd circle
=>Area of black region = π(r4)²-π(r3)²
=>Area of black region = π(42)²-π(31.5)²
=>Area of back region = 1764π - 992.25π
=>Area of black region = 771.75π
=>.°. Area of black region = 2425.5cm².
=>(5)Area of white region = Area of 5th circle - Area of 4th circle
=>Area of white region = π(r5)²-π(r4)²
=>Area of white region = π(52.5)²-π(42)²
=>Area of white region = 2756.25π -1764π
=>Area of white region = 992.25π
=>.°. Area of white region = 3118.5cm².
ANSWER :-
(1) The Area of gold region is 346.5cm².
(2)The Area of red region is 1039.5cm².
(3)The Area of blue region is 1732.5cm².
(4)The Area of black region is 2425.5cm².
(5)The Area of white region is 3118.5cm².
