Question

use Pythagoras theorem in triangle AOB​

Answer 1

Answer:

Let the triangle AOB

If AO is hypotenious

OB is base

andAB is perpendicular to OB

Then

$ao {}^{2} = ab {}^{2} + ob {}^{2}$

Answer 2

Answer:

Pythagoras theorem is also a very easy one

Step-by-step explanation:

let us draw a triangle AOB

in which right angle at O

and AB is the hypotenuse one.

AO is the perpendicular one.

OB is the base one.

so according to Pythagoras theorem:-

(AB)²=(AO)²+(OB)²