Use Pythagoreas property
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GivEn:
- Length of rectangle = 8cm
- Breadth of rectangle = 6cm
To find:
- Diagonal of rectangle ?
Solution:
• Let's consider ABCD is a rectangle.
Where,
- Base = Length = 8 cm
- Perpendicular = Breadth = 6 cm
- Hypotenus = Diagonal
• Let Breadth of rectangle be b m.
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« Now, By using Pythagoras Theorem,
→ (Perpendicular)² + (Base)² = (Hypotenuse)²
→ h² = (6)² + (8)²
→ h² = 36 + 64
→ h² = 100
→ √h² = √100
→ h = 10 cm
∴ Hence, Diagonal of the rectangle is 10 cm.
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⠀⠀⠀ ★ Additional information:
- sinθ = opp/hyp
- cosθ = adj/hyp
- tanθ = opp/adj
- cotθ = adj/opp
- cscθ = hyp/opp
- secθ = hyp/adj
- sin x = cos ( 90° - x )
- cos x = sin ( 90° - x )
- tan x = cot ( 90° - x )
- cot x = tan ( 90° - x )
- sec x = cosec ( 90° - x )
- cosec x = sec ( 90° - x )
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