Math, asked by angelharshi25, 5 hours ago

Use Pythagoreas property


Pls need it fast!

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Answers

Answered by Anonymous
16

GivEn:

  • Length of rectangle = 8cm
  • Breadth of rectangle = 6cm

To find:

  • Diagonal of rectangle ?

Solution:

• Let's consider ABCD is a rectangle.

Where,

  • Base = Length = 8 cm
  • Perpendicular = Breadth = 6 cm
  • Hypotenus = Diagonal

• Let Breadth of rectangle be b m.

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« Now, By using Pythagoras Theorem,

→ (Perpendicular)² + (Base)² = (Hypotenuse

→ h² = (6)² + (8)²

→ h² = 36 + 64

→ h² = 100

→ √h² = √100

h = 10 cm

∴ Hence, Diagonal of the rectangle is 10 cm.

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⠀⠀⠀ ★ Additional information:

  • sinθ = opp/hyp
  • cosθ = adj/hyp
  • tanθ = opp/adj
  • cotθ = adj/opp
  • cscθ = hyp/opp
  • secθ = hyp/adj
  • sin x = cos ( 90° - x )
  • cos x = sin ( 90° - x )
  • tan x = cot ( 90° - x )
  • cot x = tan ( 90° - x )
  • sec x = cosec ( 90° - x )
  • cosec x = sec ( 90° - x )
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