Question

use remainder theorem find the remainder when x cube + 3 X square + 3 X + 1 is divided by x minus 1/2

Answer 1

hiii!!!

here's ur answer...

given :-

p ( x ) = x³ + 3x² + 3x + 1

g ( x ) = x - 1/2

therefore x - 1/2 = 0

==> x = 1/2

on putting values :-

p ( 1/2 ) = (1/2)³ + 3 (1/2)² + 3 (1/2) + 1

= 1/8 + 3/4 + 3/2 + 1

= 1/8 + 6/8 + 12/8 + 8/8

= ( 1 + 6 + 12 + 8 ) / 8

= 27/8

hence, remainder is 27/8

hope this helps..!!

Answer 2

ANSWER..........

Solution: (i) x + 1

Apply remainder theorem

=>x + 1 =0

=> x = - 1

Replace x by – 1 we get

=>x3+3x2 + 3x + 1

=>(-1)3 + 3(-1)2 + 3(-1) + 1

=> -1 + 3 - 3 + 1

=> 0

Remainder is 0