Question

Use remainder theorem to find remainder when P(x) = 4x^3-12x^2+11x-5, is divided by q(x) = 1-3x.​

Answer 1

Answer:

$let \: 1 - 3x = 0.$

$then \: x = \frac{1}{3} .$

$put \: the \: value \: of \: x \: in \: p(x).$

$4 {x}^{3} - 12 {x}^{2} + 11x - 5 = 4 {( \frac{1}{3}) }^{3} - 12 {( \frac{1}{3}) }^{2} + 11( \frac{1}{3} ) - 5$

$= \frac{4}{27} - \frac{4}{3} + \frac{11}{3} - 5 = \frac{4 - 36 + 99 - 135}{27} = \frac{ - 68}{27}$

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