Use sec²θ- tan²θ=1 prove that sinθ-cosθ+1/sinθ+cosθ-1= secθ+tanθ
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Step-by-step explanation:
sinA-cosA+1/sinA+cosA-1
devide by cosA in each term
tanA-1+secA/tanA+1-secA
=tanA+secA-(sec²A-tan²A)/(tanA-secA+1)
=(secA+tanA)(1-secA+tanA)/(tanA-secA+1)
=secA+tanA
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