Question

use special expansion to find (99.9) ^2
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Answer 1

Answer:

999^2

(1000 - 1)^2

Using identity, (a - b)^2 = a^2 + b^2 -2ab

(1000 - 1)^2

(1000)^2 + (1)^2 - 2(1000×1)

1000000 + 1 - 2000

1000001 - 2000

998001