Question

Use stable identities to find the following products: (3x+4) (3x-5)​

Answer 1

Given:-

• (3x+4) (3x-5)

To find:-

• Product using suitable identity

Solution:-

$(a + b)(a - c) \\ = ( {a}^{2} ) + (b - c)(a) - (b)(c) \\ \\ \\ (3x + 4)(3x - 5) \\ = 3 {x}^{2} + (4 - 5)(3x) - (4)(5) \\ \\ \\ \green{= {9x}^{2} - 3x - 20}$

Answer 2

Given :- Use stable identities to find the following products: (3x+4) (3x-5) ?

Solution :-

we know that,

• (x + a)(x + b) = x² + (a + b)x + ab

given that,

• a = 4
• b = (-5)

so,

→ (3x + 4) * (3x - 5)

→ (3x)² + (4 - 5)3x + 4 * (-5)

→ 9x² - 3x - 20 (Ans.)

Learn more :-

Let a, b and c be non-zero real numbers satisfying (a³)/(b³ + c³) + (b³)/(c³ + a³) + (c³)/(a³ + b³)

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if a²+ab+b²=25

b²+bc+c²=49

c²+ca+a²=64

Then, find the value of

(a+b+c)² - 100 = __

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