use subset construction algorithm to find DFA for (ab)*ab
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One way to get the SoP form starts by multiplying everything out, using the distributive law: (ac+b)(a+b′c)+ac=ac(a+b′c)+b(a+b′c)+ac=aca+acb′c+ba+bb′c+ac=ac+ab′c+ab+ac=ac+ab′c+ab.
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