use substitution method 2x+y=5 x+3y=5
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2x+y=5(×3)--->equation-1
x+3y=5(×1)---->equation-2
solving equations we get
6x+3y=15
x+3y=5
(subtract all of them as they all have positive sign)
=>5x-0=10
(x=2)
substitute x value in equation-1
2(2)+y=5
4+y=5
y=5-4
(y=1)
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