Question

use suitable identities to find the following product . (3x+4y+7z)²​

Answer 1

Answer:

we can solve it by using the formula of algebraic identities

(x+y+z)^2= x^2+y^2+z^2+2xy+2yz+2zx

substituting the value of x , y, and z with 3x, 4y, and 7z we get,

=(3x)^2 +(4y)^2 +(7z)^2 + 2×3x×4y + 2×4y×7z + 2×7z×3x

= 9x^2 + 16y^2+ 49z^2 + 24xy + 56yz + 42zx