Question

. Use suitable identities to find the following products:
(1) (x+4) (x + 10)
(ii) (x + 8) (x-10)
3
3
(iv) (y2 +
3) 12-
(v) (3 - 2x) (3 + 2x)
2​

Answer 1

Answer:

(i) (x+4)(x+10)

using identity (x+a)(x+b)=x2+(a+b)x+ab

x2+(4+10)x+4(10)

x2+14x+40

(ii) (x+8)(x−+(−10))

x2+(8−10)x+8(−10)

=x2−2x−80

(iii) (3x+4)(3x−5)

(3x)2+(4−5)(3x)+4⋅(−5)

=9x2−3x−20

(iv) (y2+32)(y2−32)

=(y2)2−(32)2=y4−94

(v) (3−2x)(3+2x)

(3)2−(2x)2

9−22x2

9−4x2

answer

Step-by-step explanation:

Answer 2

Answer:

8

Step-by-step explanation:

x+4x+40

5x×40

x= 8

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