Question

use suitable identities (x+1)²-(y-1)²​

Answer 1

Step-by-step explanation:

Let's consider "a" as x+1

and "b" as y -1

We know that: (a)² - (b)² = (a+b)(a-b)

Using this identity,

[ (x+1) + (y-1) ] [ (x+1) - (y-1) ]

→(x+y)(x+1 - y +1)

→(x+y)(x-y+2)

→x(x) + y(-y) + x(2) + y(2)

→x² - y² + 2x + 2y

→ x² - y² + 2(x+y)

Hope it helps.

★Additonal Information:-

The equation can be more factorised. It's not really needed as it's not mentioned, but here :

x² - y² + 2(x+y)

As we know the identity a²-b² = (a+b)(a-b)

(x+y)(x-y)+2(x+y)

and so on...