Question

use suitable identity and solve (x-8)(x+4) and (2x+3)(2x-3)​

Answer 1

Let's simplify step-by-step.

$(x−8)(x+4)+(2x+3)(2x−3)$

Distribute:

$=(x)(x)+(x)(4)+(−8)(x)+(−8)(4)+(2x)(2x)+(2x)(−3)+(3)(2x)+(3)(−3)$

$= {x}^{2} +4x+−8x+−32 + {4x}^{2} + - 6x + 6x + - 9$

Combine Like Terms:

$= \blue{( {x}^{2} + 4 {x}^{2} )} + \green{(4x+−8x+−6x+6x)} + \red{(−32+−9)}$

$\large = \blue{ {5x}^{2} } + \green{ - 4x} + \red{ - 41}$