Question

use suitable identity of the following (2y+5)(2y+5)​

Answer 1

Step-by-step explanation:

To solve :- ( 2 y + 5 ) ( 2 y + 5 )

Solution :-----

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Formula to be used →

1) ( a + b ) ( a + b ) = ( a + b) ^2

And ,

2) ( a + b )^2 = a^2 + b^2 + 2ab .

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Final solution:-

• ( 2y + 5 ) ( 2y + 5 )

= ( 2y + 5 ) ^2 [ Using the formula number 1 ]

{ Assuming 2y is equal to a and 5 is equal to b }

= ( 2 y ) ^2 + 5^2 + 2× 2y × 5 [ Using the formula number 2]

Simplifying the expression we get

= 4y ^2 + 25 + 20y

Writing in quadratic equation format →

= 4y ^2 + 20y + 25 .

Hence , the required answer is 4y^2 + 20y + 25 .

Answer 2

The product will be as follow

(2y + 5) (2y + 5) = (2y + 5)2

= (2y)2 + 2(2y) (5) + (5)2 [(a + b)2 = a2 + 2ab + b2]

= 4y2 + 20y + 25

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