Question

use suitable identity to find the product (2a+5b)^2​

Answer 1

Answer:

Product of $(2a+5b)^{2}=4a^{2} +20ab+25b^{2}$

Step-by-step explanation:

Given the equation, $(2a+5b)^{2}$

The equation is in the form of $(a+b)^{2}$

which can be expanded using the identity

                       $(a+b)^{2}=a^{2} +2ab+b^{2}$

Therefore, $(2a+5b)^{2}=(2a)^{2} +2(2a)(5b)+(5b)^{2}$

                                   $=4a^{2} +20ab+25b^{2}$

Answer 2

Answer:

The product of $(2a+5b)^{2}$ is $4a^{2} + 20ab+25b^{2}$

Step-by-step explanation:

We have been given the equation, $(2a+5b)^{2}$

Here we will use the identity, $(a^{2} +b^{2} ) = a^{2} +b^{2} +2ab$

Now, substituting the values in the above equation we get,

$(2a+5b)^{2} = (2a)^{2} + (5b)^{2} + 2(2a)(5b)$

$= 4a^{2} +25b^{2} +20ab$

$= 4a^{2} +20ab+25b^{2}$

Hence, the product of $(2a+5b)^{2}$ is $4a^{2} + 20ab+25b^{2}$

#SPJ2