Question

Use suitable identity to find the product of

(a-b-c)(a^2+b^2+c^2+ab+ac-bc)

Answer 1

(a-b-c)(a²+b²+c²+ab-bc+ca)

=a³-b³-c³-3abc

Step-by-step explanation:

we know the algebraic identity:

(x+y+z)(x²+y²+z²-xy-yz-zx)

=x³+y³+z³-3xyz--(1)

Now,

we have ,

(a-b-c)(a²+b²+c²+ab-bc+ca)

=[a+(-b)+(-c)][a²+(-b)²+(-c)²-a(-b)-(-b)(-c)-(-c)a]

= a³+(-b)³+(-c)³-3a(-b)(-c)

= a³-b³-c³-3abc /* From (1)

Therefore,

(a-b-c)(a²+b²+c²+ab-bc+ca)

=a³-b³-c³-3abc

hope it helps u

Answer 2

Answer:

a^3 - b^3 - c^3 - 3abc

Step-by-step explanation:

hope it helps :)