use suitable identity to (y^2 - 4) (y^2 – 3)
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Answered by
1
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it s x^2-a × x^2-by
2
−4)(y
2
−3)
{y}^{4} - 3 {y}^{2} - 4 {y}^{2} + 12y
4
−3y
2
−4y
2
+12
{y}^{4} - 7 {y}^{2} + 12y
4
−7y
2
+12
Step-by-step explanation:
hope it's helpful
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