Math, asked by yashjadhao, 4 months ago

use suitable identity to (y^2 - 4) (y^2 – 3)

Answers

Answered by tejaswimehta05
2

Answer:

( {y}^{2}  - 4)( {y}^{2}  - 3)

 {y}^{4}  - 3 {y}^{2}  - 4 {y}^{2}  + 12

 {y}^{4}  - 7 {y}^{2}  + 12

Answered by amkumar2005
1

Answer:

it s x^2-a × x^2-by

2

−4)(y

2

−3)

{y}^{4} - 3 {y}^{2} - 4 {y}^{2} + 12y

4

−3y

2

−4y

2

+12

{y}^{4} - 7 {y}^{2} + 12y

4

−7y

2

+12

Step-by-step explanation:

hope it's helpful

Similar questions