use suitable special products to find each of the following: ( a/2 - 3 ) ( a/2 - 9 )
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0
Answer:
a^2/4+6a+18
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Answered by
1
Answer:
[(x-a) (x-b) = x^2-ax-bx+ab]
(a/2-3) (a/2-9)= a^2/4-3a/2-9a/2+27
=>a^2-12a/2+27
=>a^2-6a+27.
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